Reference News Network, December 13 report, according to Russia's Lenta.ru, on December 11, 2017, Russian Foreign Minister Lavrov outwitted the CIA, exposing an American spy who had infiltrated the Kremlin.
In 2017, after U.S. President Trump met with Lavrov, Washington ordered the withdrawal of one of its key intelligence personnel from Russia. It is speculated that during the meeting, Trump accidentally revealed some classified information, indicating that there was a U.S. spy lurking in the Kremlin. The spy was Oleg Smolenkov, who was almost immediately dismissed from the Kremlin Office after the meeting between Trump and Lavrov, and then fled Russia with his family. CNN said that Smolenkov was one of the "most valuable agents" working within the Russian power structure.
According to Andrey Popov, a member of the veteran association of Russia's Alpha Group special forces and a reserve colonel of the Federal Security Service (FSB), it was Lavrov who created the appropriate conditions during the meeting to make the CIA nervous and actively withdrew the spy.
Maria Zakharova, a spokesperson for the Russian Foreign Ministry, said that the Russian Foreign Ministry has requested the U.S. to provide information about Smolenkov's whereabouts. This person has been referred to by the media as a CIA informant.
Zakharova emphasized that Russia has sought assistance from Interpol. Smolenkov disappeared from Russia with his family, and Russia has opened an investigation into this case, which remains unsolved to date.
Interpol refused to comment on Russia's request to investigate Smolenkov's whereabouts and pointed out that Interpol only shares information with member states within the framework of bilateral cooperation. (Translated by Li Ran)
Original: toutiao.com/article/7583285483380163112/
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